EL calculations for CR 1 or less

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Archived from groups: rec.games.frp.dnd (More info?)

Okay, so I do a lot of messing around with calculating ELs for complex
groups. And it came as a shock to me recently when someone pointed out that
the calculating formula is not simply based on [add +2 to EL for every
doubling of creatures] since they list an important exception: CR 1.

Well, fractional CRs are also an exception, ie., two orcs do not make EL 2
1/2. That much was obvious.

But I always thought 2 CR 1 creatures = EL 3. And to go with that, 4 orcs =
EL 3.

Now, I realize the poster was right and the DMG does say 2 CR 1 creatures =
EL 2 and 4 orcs = EL 2.

This leads to bizarre things such as: Any party of 4 PCs meeting a party of
4 NPCs of their level is in for a Very Difficult encounter with generally
even odds of TPK (ie., EL = party level + 4) -- except for a 1st level party
who supposedly have an easier time of it (EL = party level + 3).

Okay, forgetting that, can anyone see WHY the DMG breaks with the general
principle that doubling creatures adds 2 for CR 1 only? Is there something
strange about the CR 1 creature type that makes this come out this way and
makes it logical?

I'm asking this not only for the theoretical sanity of it all (before I go
redo all my EL calc tables) but also
 
Archived from groups: rec.games.frp.dnd (More info?)

Spinner wrote:

> Okay, forgetting that, can anyone see WHY the DMG breaks with the
general
> principle that doubling creatures adds 2 for CR 1 only? Is there
something
> strange about the CR 1 creature type that makes this come out this
way and
> makes it logical?

There is a reason, but it doesn't neccessarily have anything to
do with how dangerous the encounters actually are.

EL typically gives (approximately) total EP if you treat an
encounter as a single monster of CR=EL. In fact for cases where
all foes give EP this is as accurate as possible given the table
precission and round-off rules they are using.

This makes sense, two EL 6 encounters are about the same difficulty
so they should give about the same EL baring ad-hoc adjustments
to EL or EP.

The "normal" EP formula would give EP awards for CR 1, 2, and 3
as follows for levels 1-3:
Level 1: 300, 400, 600
Level 2: 400, 600, 800
Level 3: 450, 600, 900

Which is wonky with higher levels getting more EP, so they use
the level 3 line for everybody from level one to three.

Which is wonky since then a level 1 party would advance after
only 8.88888 encounters with appropriate encounters rather
than 13.33333. So they reduced to only 300 EP the CR one award
on the level 1-3 line of the table. (And for levels 4-6 they
retained a value of 300 rather than using the slightly higher
values a formula would give.)

Reduced EP for CR 1 means they also use reduced EL for encounters
with multiple level 1 foes, since if they did not the CR 1 foes
would give too little EP per encounter at equal EL.

Basically level 1 characters get too much EP for everyone above
CR 1, and everyone else up to about level 6 gets too little for
CR 1 foes. This is done to make the EP table work, but the
result is that CR 1 gives less EP than you would expect compared
to higher CR foes up until level 6. So they alse reduced the
significance of multiple CR 1 foes relative to CR 2 and 3 in
calculating EL.

For more on the EP table see my post
with ID:
1106866804.151803.198200@c13g2000cwb.googlegroups.com

DougL
 
Archived from groups: rec.games.frp.dnd (More info?)

> I'm asking this not only for the theoretical sanity of it all (before I go
> redo all my EL calc tables) but also
Sorry -- to continue here, ...

.... but also because I'm prepping a 1st level adventure now and want to know
how many orcs I *should* throw at my party.

I know EL calculations are not a precise science but I wonder what people
have to say about what I perceive here as an anomaly....

Spinner
 
Archived from groups: rec.games.frp.dnd (More info?)

Spinner wrote:

> Okay, so I do a lot of messing around with calculating ELs for complex
> groups. And it came as a shock to me recently when someone pointed out that
> the calculating formula is not simply based on [add +2 to EL for every
> doubling of creatures] since they list an important exception: CR 1.
>
> Well, fractional CRs are also an exception, ie., two orcs do not make EL 2
> 1/2. That much was obvious.
>
> But I always thought 2 CR 1 creatures = EL 3. And to go with that, 4 orcs =
> EL 3.
>
> Now, I realize the poster was right and the DMG does say 2 CR 1 creatures =
> EL 2 and 4 orcs = EL 2.

Does this extrapolate to larger hordes? Are 8 orcs EL 3 or EL 4 (+1 or
+2 for the doubling)?

I think the difference is that EL 1 and lower monsters are piddling
little things that a mid-level party will be able to carve a swath
through without much trouble.

- Ron ^*^


- Ron ^*^
 
Archived from groups: rec.games.frp.dnd (More info?)

Spinner wrote:
> >> Okay, forgetting that, can anyone see WHY the DMG breaks with the
> > general
> >> principle that doubling creatures adds 2 for CR 1 only? Is there
> > something
> >> strange about the CR 1 creature type that makes this come out this
> > way and
> >> makes it logical?
> >
> > There is a reason, but it doesn't neccessarily have anything to
> > do with how dangerous the encounters actually are.
> >
> Basically you say below that it's because of experience point values,
not
> because of power. So does that mean that you think the book supports
the
> concept that two CR 1 monsters have about the power of an EL 2
encounter or
> an EL 3? That is, is it just a kludge for making the xp work out
right or
> is CR 1 really half as powerful as CR 2?

I think it is a cludge to make EP work out right. It may also be
half as powerful (I doubt it), but the reason is that EP and EL
should match.

> > EL typically gives (approximately) total EP if you treat an
> > encounter as a single monster of CR=EL. In fact for cases where
> > all foes give EP this is as accurate as possible given the table
> > precission and round-off rules they are using.
> >
> > This makes sense, two EL 6 encounters are about the same difficulty
> > so they should give about the same EL baring ad-hoc adjustments
> > to EL or EP.
> >
> > The "normal" EP formula would give EP awards for CR 1, 2, and 3
> > as follows for levels 1-3:
> > Level 1: 300, 400, 600
> > Level 2: 400, 600, 800
> > Level 3: 450, 600, 900
> >
> > Which is wonky with higher levels getting more EP, so they use
> > the level 3 line for everybody from level one to three.
> >
> This is where you lost me -- can you explain this table? IDHMDMGIFOM
and of
> course I can't get this out of the SRD! It seems like this is
crucial to
> your explanation below.

The EP table in the DMG is based on four simple rules:
1) An equal CR foe is worth 300xCR EP at every level.
2) +2 CR is worth x2 EP; -2 CR is worth x1/2 EP
3) When CR differs from level by an odd number round off as if +1
CR were worth character level x 400 EP (which is quite close to
times square root two).
4) Truncate the table at absolute value (CR-ECL)>8.

These rules can be combined into a single formula:
EP = 300 * ECL * 2^(CR-ECL/2)
With round off for odd CR-ECL very slightly modifying the result, and
large differences in CR and ECL being thrown out. This reproduces every

EP value they give except for the ECL 1-3 row, and the CR 1 column.

For ECL 1-3 they combined and used the results for ECL 3, which are
almost identical to those for ECL 2 in any case, and for the CR 1
column they applied a maximum award of 300 EP.

> For example, what is the "normal" EP formula you refer to here? Why
does
> the xp get higher with level here?

EP gets higher with level because ECL 3 vs. CR 3 has to give 900
EP. (their basic rule for advancement at 13.3333 "patrol" encounters
demands this), but the standard rule for ECL 1 is 300 EP for CR 1,
and double for +2 CR, which of course gives only 600 EP.

So combining the two basic rules for EP awards for a given CR
we get higher awards at level 2 & 3 than at level 1.
The basic design decisions, constant advancement rate, power
roughly doubles every 2 levels, and EP needed to advance goes
up linearly dictate this result.

Basically if you look at the formula above, the EP award for a
constant CR has one term that goes UP liniarly with level, and
a second that comes DOWN exponentially with level.

We think of exponential growth as faster than liniar, but that
is only true as the independent variable gets "large", in this
case large happens to be at about level 3, prior to that the
liniar term is actually more significant. So they throw out
the results for levels 1 and 2 which give the wonky result.

> > Which is wonky since then a level 1 party would advance after
> > only 8.88888 encounters with appropriate encounters rather
> > than 13.33333. So they reduced to only 300 EP the CR one award
> > on the level 1-3 line of the table. (And for levels 4-6 they
> > retained a value of 300 rather than using the slightly higher
> > values a formula would give.)
> >
> > Reduced EP for CR 1 means they also use reduced EL for encounters
> > with multiple level 1 foes, since if they did not the CR 1 foes
> > would give too little EP per encounter at equal EL.
> >
> > Basically level 1 characters get too much EP for everyone above
> > CR 1, and everyone else up to about level 6 gets too little for
> > CR 1 foes. This is done to make the EP table work, but the
> > result is that CR 1 gives less EP than you would expect compared
> > to higher CR foes up until level 6. So they alse reduced the
> > significance of multiple CR 1 foes relative to CR 2 and 3 in
> > calculating EL.
> >
> > For more on the EP table see my post
> > with ID:
> > 1106866804.151803.198200@c13g2000cwb.googlegroups.com
> >
> Thanks for all this reply -- I couldn't follow this link BTW.

Go to advanced search in Google groups and paste that into
the Message ID search, it works fine for me.

But I basically just repeated it with different emphasis.

Alternately whatever browser you use should have some way to
search on message ID, it may want the ID enclosed in < >;
although the message may have expired off your server so I
recomend Google in this case.

DougL
 
Archived from groups: rec.games.frp.dnd (More info?)

>> Okay, forgetting that, can anyone see WHY the DMG breaks with the
> general
>> principle that doubling creatures adds 2 for CR 1 only? Is there
> something
>> strange about the CR 1 creature type that makes this come out this
> way and
>> makes it logical?
>
> There is a reason, but it doesn't neccessarily have anything to
> do with how dangerous the encounters actually are.
>
Basically you say below that it's because of experience point values, not
because of power. So does that mean that you think the book supports the
concept that two CR 1 monsters have about the power of an EL 2 encounter or
an EL 3? That is, is it just a kludge for making the xp work out right or
is CR 1 really half as powerful as CR 2?

> EL typically gives (approximately) total EP if you treat an
> encounter as a single monster of CR=EL. In fact for cases where
> all foes give EP this is as accurate as possible given the table
> precission and round-off rules they are using.
>
> This makes sense, two EL 6 encounters are about the same difficulty
> so they should give about the same EL baring ad-hoc adjustments
> to EL or EP.
>
> The "normal" EP formula would give EP awards for CR 1, 2, and 3
> as follows for levels 1-3:
> Level 1: 300, 400, 600
> Level 2: 400, 600, 800
> Level 3: 450, 600, 900
>
> Which is wonky with higher levels getting more EP, so they use
> the level 3 line for everybody from level one to three.
>
This is where you lost me -- can you explain this table? IDHMDMGIFOM and of
course I can't get this out of the SRD! It seems like this is crucial to
your explanation below.

For example, what is the "normal" EP formula you refer to here? Why does
the xp get higher with level here?

> Which is wonky since then a level 1 party would advance after
> only 8.88888 encounters with appropriate encounters rather
> than 13.33333. So they reduced to only 300 EP the CR one award
> on the level 1-3 line of the table. (And for levels 4-6 they
> retained a value of 300 rather than using the slightly higher
> values a formula would give.)
>
> Reduced EP for CR 1 means they also use reduced EL for encounters
> with multiple level 1 foes, since if they did not the CR 1 foes
> would give too little EP per encounter at equal EL.
>
> Basically level 1 characters get too much EP for everyone above
> CR 1, and everyone else up to about level 6 gets too little for
> CR 1 foes. This is done to make the EP table work, but the
> result is that CR 1 gives less EP than you would expect compared
> to higher CR foes up until level 6. So they alse reduced the
> significance of multiple CR 1 foes relative to CR 2 and 3 in
> calculating EL.
>
> For more on the EP table see my post
> with ID:
> 1106866804.151803.198200@c13g2000cwb.googlegroups.com
>
Thanks for all this reply -- I couldn't follow this link BTW.

Spinner
 
Archived from groups: rec.games.frp.dnd (More info?)

>> That is, is it just a kludge for making the xp work out
> right or
>> is CR 1 really half as powerful as CR 2?
>
> I think it is a cludge to make EP work out right. It may also be
> half as powerful (I doubt it), but the reason is that EP and EL
> should match.
>
Good to know. I'll ignore it for power purposes then.

>> > The "normal" EP formula would give EP awards for CR 1, 2, and 3
>> > as follows for levels 1-3:
>> > Level 1: 300, 400, 600
>> > Level 2: 400, 600, 800
>> > Level 3: 450, 600, 900
>> >
>> > Which is wonky with higher levels getting more EP, so they use
>> > the level 3 line for everybody from level one to three.
>> >
>> This is where you lost me -- can you explain this table?
> The EP table in the DMG is based on four simple rules:
[snip]
Thanks for taking the time to dole out to me the full explanation. I
believe I understand it now having read through. Makes sense even if it
does produce kludgeage.

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