Fuel usage

G

Guest

Guest
Archived from groups: alt.games.vgaplanets4 (More info?)

Like it is with guesses: Sometimes they are wrong. I assumed more complexity for the fuel comsumption as there actual is. So
excuse me and here it is how it should work:

First calculate the fuel consumption per kT and lj at given speed V as
q(v) = B(i) * ( 2^i * v / MaxV)^2 * WarpDrag/100 * (100%-PMBonuses)
MaxV is the max speed of the used engines
PMBonuses is the sum of the percentual plasma manifolds exotic tech bonuses
WarpDrag ist the warp drag factor of the used hull
i is either 2,1 or 0 and is dependent of in which interval of the three
[0, MaxV/4) [MaxV/4, MaxV/2) [MaxV/2, MaxV] the vlaues of v is.
B(i) is the either vC/4-K/100000 or vC/2-K/100000 or vC-K/100000
This are the burn rates per kTlj at the speeds MaxV/4, MaxV/2 and MaxV
Then the fuel consumption DF(d,v) as a function of the total distance d, which can be traveled within the next turn is at travel
speed v is given by

DF(d,v) = M*q(v)*d where M is the total mass at the beginning of the movement.

If one now sends a ship over several turn to a distant target and one wants to know how mach fuel is
needed then one have to do the following:

Assume the speed stays constant and only the fuel load is allowed to change due to fuel burning by the movement.

Then one can write abbreviated

Fn+1 = Fn-(Fn+H) q d = Fn(1-q d) -H q d

which leads to

Fn=F0 (1-qd)^n - H (1- (1-qd)^n)

d is here the distance which can be traveled within a whole turn.

Then one gets the fuel consumption over a distance of an integral multiple of d as

DF = M*( 1 - [1- q(v)*d]^n )
_______________________

n is the number of turns.

If one wants to know how many turns a fuel load lasts then one have resolve

for n:

n = LN[ H/(F+H)] / LN[1-q(v)*d]
___________________________


Here H is the total mass without the fuel mass.

If one wants to know how many fuel one have to take for the journey then one have to resolve

F=(H+F) (1 - [1- q(v)*d]^n ) for F:


F= H ( [1- q(v)*d]^(-n) -1 )
______________________


I hope this time it fits.


As mentioned changing orders for the plasma manifold exotechs are not displayed and also the client seems to display the mass of
the last turn. So one have to calculate the the mass manually.

The mass depends on

- nacked hull mass
- SupWs
- LWs
- SW, each 1kT
- PD, each 1kT
- Engines, each 1KT (?)
- personnel, 100 personnel=1kT
- Cargo load, don't forget pods
- docked Wings (?)
- Ord&Rep load, (?)
- Fuel load
- mc, 1000mc=1kT (?)
- Armor (?)


GFM GToeroe
 
Archived from groups: alt.games.vgaplanets4 (More info?)

Gabor Törö wrote:
> I hope this time it fits.

Not really read it, but I think it still does not fit.
Why?
Well I will give a short example:
Assume you have a dozen or so Borg Probes all with just 1 kt of fuel
and
the worst warp drives (tech 1). Let them fly with max speed - fuel
consumption will in that case nearly always be zero (the displayed one
by the client), but as it is within a few turns all of them will run
out of fuel, but then again not all at the same time.
Of course since the game (Muchobongaphobia) I did experience it was in
2002 somethings might have changed about it, but then again I doubt
that.
 
Archived from groups: alt.games.vgaplanets4 (More info?)

"Nameless" <unknown_ai@web.de> schrieb im Newsbeitrag news:1115826547.634245.175890@z14g2000cwz.googlegroups.com...
Gabor Törö wrote:
> I hope this time it fits.

>the worst warp drives (tech 1). Let them fly with max speed - fuel
>consumption will in that case nearly always be zero (the displayed one
>by the client), but as it is within a few turns all of them will run
>out of fuel, but then again not all at the same time.

Ok, this could be due to the fact that fuel is not an integer and the client only displays the integral part.
And I assume they have a accuracy of a few kT what would be enough if one loads a smal reserve of 10 kT

GFM GToeroe