H67 Mobo and CPU OC

[kknd2]

I'm using a Asus P8H67-m Pro motherboard. I know that H67 shouldn't be able to overclock. but here
http://www.hardwaresecrets.com/article/ASUS-P8H67-M-PRO-CSM-Motherboard/1376/7
it says this Mobo has all sorts of overclocking options.
so my question is can this thing overclock K series CPUs?

PS: I have this mobo for a few years already so no need to say anything about getting another mobo ;D!

 

[ewok93]

The motherboard can overclock.

 

[kknd2]

The motherboard can overclock.

uhm.. I'm not very good with OCing cpus. i know that the cpu ratio cannot exceeds x34, but the baseclock can go up to 300mhz. Do people with Zchipset mobo + K series cpu normally crank up their ratio or baseclock or both?

 

[kknd2]

The motherboard can overclock.

uhm.. I'm not very good with OCing cpus. i know that the cpu ratio cannot exceeds x34, but the baseclock can go up to 300mhz. Do people with Zchipset mobo + K series cpu normally crank up their ratio or baseclock or both?

 

[ewok93]

Basically in overclocking you have two things you can change, the base clock and the ratio. For example, my 8320 has a base clock of 200, and I set the multiplier to 22. That means the clock speed will be 4.4ghz, or 4400mhz. Generally, it's easiest to just change the ratio. What setup are you looking at, exactly?

 

[kknd2]

Basically in overclocking you have two things you can change, the base clock and the ratio. For example, my 8320 has a base clock of 200, and I set the multiplier to 22. That means the clock speed will be 4.4ghz, or 4400mhz. Generally, it's easiest to just change the ratio. What setup are you looking at, exactly?

well I have the impression that raising the base clock will mess up your memory too, thus it is frowned upon in cpu overclocking scenarios. As to a set up. I'm thinking of a 2500K or 2600k with 4.5ghz. because the mobo cannot go ass x34 multiplier, that means i need to raise the BCLK. Would you recommend bumping the bclk (to whatever is needed) and keep the multiplier @ x34? Would that be stable?