Help with syntax

[bsnowman17]

bit_X = ((byte_Y & 0x80) ? 1 : 0);

Could someone explain what is happening here?

X is a bit
Y is a byte

 

[Ijack]

The expression on the right tests whether the leftmost bit of byte_Y is set. If so it sets bit_X to 1, otherwise it sets it to 0.

byte_Y & 0x80

Is the test (0x80 is 10000000 in binary).

(A ? 1 : 0)

Is the conditional.

 

[bsnowman17]

Best answer selected by bsnowman17.

 

[Dark Lord of Tech]

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