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Archived from groups: rec.games.trading-cards.jyhad (More info?)
> Suggested group rule:
> Each player must have at least 12 cards in her crypt, which may be
from
> any group or two consecutive groups. Additional groups may be used,
> increasing that player's crypt minimum by an additional 12 cards per
> group.
The probability of drawing a given vampire at a given time (other than
the first drawn vampire) is a dependent event.
As a 12-card crypt with no duplicates is increased to become a 24-card
crypt, composed of exactly 2 copies of each vampire, and on to a
32-card crypt composed of 3 copies of each, etc., the probability of
drawing a given vampire approaches an independent event.
Visually,
17 000 copies Mustafa Rahman
17 000 copies Jing Wei
17 000 copies Sarah Cobbler
etc., your chances of drawing Sarah Cobbler will approach .08333, or
8.333%, as these numbers increase. This means that the benefit of
adding more choices continues to increase, as the drawback of
increasing crypt size ceases to add any practical penalty.
So you used, say, 12 groups, this is still virtually dial-a-crypt, only
you have to buy a LOT of cards.
The solution above should be amended to "One additional group may be
used...". Or perhaps two, but I haven't done the math.
Statisticians? Anyone?
-- Brian
Actually in favor of even-and-odd
> Suggested group rule:
> Each player must have at least 12 cards in her crypt, which may be
from
> any group or two consecutive groups. Additional groups may be used,
> increasing that player's crypt minimum by an additional 12 cards per
> group.
The probability of drawing a given vampire at a given time (other than
the first drawn vampire) is a dependent event.
As a 12-card crypt with no duplicates is increased to become a 24-card
crypt, composed of exactly 2 copies of each vampire, and on to a
32-card crypt composed of 3 copies of each, etc., the probability of
drawing a given vampire approaches an independent event.
Visually,
17 000 copies Mustafa Rahman
17 000 copies Jing Wei
17 000 copies Sarah Cobbler
etc., your chances of drawing Sarah Cobbler will approach .08333, or
8.333%, as these numbers increase. This means that the benefit of
adding more choices continues to increase, as the drawback of
increasing crypt size ceases to add any practical penalty.
So you used, say, 12 groups, this is still virtually dial-a-crypt, only
you have to buy a LOT of cards.
The solution above should be amended to "One additional group may be
used...". Or perhaps two, but I haven't done the math.
Statisticians? Anyone?
-- Brian
Actually in favor of even-and-odd