Archived from groups: rec.games.roguelike.nethack (
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John Campbell wrote:
> Benjamin Lewis wrote:
>> Haakon Studebaker wrote:
>>
>>> My invisible monk wearing an amulet of reflection was zapped by a
>>> wand. The beam bounced off him because of the amulet! How can something
>>> reflect if one can not perceive the reflected surface?
>> That depends on how invisibility and reflection "work". This may or may
>> not be relevant, but ultraviolet and infrared light can reflect off
>> objects, and you cannot see light in these wavelengths. For example,
>> it's certainly possible, at least in theory, to have a surface that
>> transmits light in the visible spectrum and is therefore invisible (at
>> least, if it has an index of refraction the same as the air around it),
>> but that reflects ultraviolet or infrared light.
>>
> Not relevant, I think. Of the attacks that reflection protects
> against - beams of death, disintegration, cold, fire, magic missile,
> sleep, acid, lightning, and Medusa's and floating eyes' gaze - only the
> last three involve the electromagnetic spectrum to any degree greater
> than as pretty special effects.
I was just using these examples as an analogy.
> And reflection doesn't help against pure light-based attacks like
> exploding yellow lights or the blinding flash of lightning bolts (even
> when the bolt itself is reflected).
> It's not that reflection and
> invisibility are operating on different frequency bands; they're
> operating in totally different media.
>
> Medusa's gaze somewhat confuses the issue, though. I'm not sure
> why reflection should protect against Medusa and floating eyes but not
> against pyrolisks or Archons, and that reflection protects against her
> gaze whether the PC is visible or not, but only bounces back and
> petrifies her when the PC is visible seems logically inconsistent.
There are two components to Medusa's gaze: the visible (EM radiation)
component and the magic component. Both of these are required for the
stoning effect. When the character is invisible and has reflection, the
magic component gets reflected but the EM component does not, so neither
the transmitted nor the reflected component are effective. If the
character is visible, both components are reflected, and Medusa gets
stoned.
> When you then further consider that she can be petrified with an
> invisible mirror, but not with an invisible shield of reflection, logic
> just packs it in.
Um.
<scratches head>
I can't explain this, but I note that one has to explicitly (a)pply the
mirror, so this would probably be a good place to start searching for the
explanation.
--
Benjamin Lewis
Although the moon is smaller than the earth, it is farther away.