[SOLVED] Pattern (Syntax) for non-negative numbers in CMD?

[AlvinSeville]

Hello! I'm trying to type pattern for non-negative numbers. When I execute the following command:

echo 2223 | findstr /r "^[0-9][0-9]*$ ^+[0-9][0-9]*$"

nothing is printed (there is no match found). How to fix it? I expected 2223 as output.

Here are some examples:

• Input: "2223", Output: "2223"
• Input: "a2223", Output: ""
• Input: "2223b", Output: ""
• Input: "a", Output: ""
• Input: "a 2223", Output: ""
• Input: "2223 b", Output: ""

In general case if input string contains only digits (and may be "+" before them) then entire string must printed as output, but if there are some non-number symbols such as letters then nothing must be as result.

I wan't to understand which syntax to use to write '^[0-9]+$' grep equivalent:

echo "2223" | grep --color -E '^[0-9]+$'

I know that I can use Bash on Windows (via Cygwin for instance) but it is interesting to figure out how to use regex in cmd.

 

[Ralston18]

I am not sure that I understand your overall requirement.

More explanation is needed.

Provide a couple of specific examples of the "input" and what you expect or require as "output".

Use 2223 if that is applicable and appropriate.

 

[AlvinSeville]

Here are some examples:

• Input: "2223", Output: "2223"
• Input: "a2223", Output: ""
• Input: "2223b", Output: ""
• Input: "a", Output: ""
• Input: "a 2223", Output: ""
• Input: "2223 b", Output: ""

If input string contains only digits (and may be "+" before them) then entire string must printed as output, but if there are some non-number symbols such as letters then nothing must be as result.

(I've also added this in the first message.)

 

[AlvinSeville]

Solution is found:

echo 2223| findstr /r "^[0-9][0-9]*$ ^+[0-9][0-9]*$"

Space after number was removed to solve my problem.