# x cost, order of math (lsj)

G

#### Guest

##### Guest

in this example, i have una, with the eye of hazimel, clan impersonated
to tremere, and the ankara citadel.
the card i want to use is hidden strength, which has x as its cost.
let's say some big mf like the beast hits me for 10 (with his +1 str,
and an undead strength after tossing 3 increased strengths.) can i use
the math to my best advantage? if i say x is 9 (to prevent all 10
damage,) and i figure it one way, the eye subtracts 1 from a combat
card's cost, una's special subtracts 1 from a fortitude card's cost,
taking us to x=7, and half that rounding down is 3, for the citadel.
but if i halve the cost first, x/2 rounded down is 4, then i subtract 1
twice for the other 2 reductions, and i only end up paying 2...
there doesn't seem to be any clarification i've found stating that the
subtractions would come before the halving, and regular math would vary
according to the parentheses.
hoping for the cornercase math of the week award,
john spore

(x-1-1)/2
(x/2)-1-1

G

#### Guest

##### Guest

On 6 Mar 2005 22:06:13 -0800, "SPORE" <sporemage37@hotmail.com>
scrawled:

>in this example, i have una, with the eye of hazimel, clan impersonated
>to tremere, and the ankara citadel.
>the card i want to use is hidden strength, which has x as its cost.
>let's say some big mf like the beast hits me for 10 (with his +1 str,
>and an undead strength after tossing 3 increased strengths.) can i use
>the math to my best advantage? if i say x is 9 (to prevent all 10
>damage,) and i figure it one way, the eye subtracts 1 from a combat
>card's cost, una's special subtracts 1 from a fortitude card's cost,
>taking us to x=7, and half that rounding down is 3, for the citadel.
>but if i halve the cost first, x/2 rounded down is 4, then i subtract 1
>twice for the other 2 reductions, and i only end up paying 2...
>there doesn't seem to be any clarification i've found stating that the
>subtractions would come before the halving, and regular math would vary
>according to the parentheses.
>hoping for the cornercase math of the week award,

Una and eye both reduce the cost.

ankara does not effect the cost. it effects how much blood they have
to spend for the given cost.

work out cost first (Una and Eye).
9-2 = 7

then work out how much blood to pay for that cost (ankara).
7/2 = 3.5, rounded down to 3.

salem
(replace "hotmail" with "yahoo" to email)

G

#### Guest

##### Guest

salem wrote:
> On 6 Mar 2005 22:06:13 -0800, "SPORE" <sporemage37@hotmail.com>
> scrawled:
>
>
>>in this example, i have una, with the eye of hazimel, clan impersonated
>>to tremere, and the ankara citadel.
>>the card i want to use is hidden strength, which has x as its cost.
>>let's say some big mf like the beast hits me for 10 (with his +1 str,
>>and an undead strength after tossing 3 increased strengths.) can i use
>>the math to my best advantage? if i say x is 9 (to prevent all 10
>>damage,) and i figure it one way, the eye subtracts 1 from a combat
>>card's cost, una's special subtracts 1 from a fortitude card's cost,
>>taking us to x=7, and half that rounding down is 3, for the citadel.
>>but if i halve the cost first, x/2 rounded down is 4, then i subtract 1
>>twice for the other 2 reductions, and i only end up paying 2...
>>there doesn't seem to be any clarification i've found stating that the
>>subtractions would come before the halving, and regular math would vary
>>according to the parentheses.
>>hoping for the cornercase math of the week award,
>
>
> Una and eye both reduce the cost.
>
> ankara does not effect the cost. it effects how much blood they have
> to spend for the given cost.
>
> work out cost first (Una and Eye).
> 9-2 = 7
>
> then work out how much blood to pay for that cost (ankara).
> 7/2 = 3.5, rounded down to 3.

Correct.

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