360 terabytes of data on a 5-inch square
video:
10800×4320×120×48/8×60×60×3 = 362 797 056 000 000
audio:
192000×(22+2+4)×32/8×60×60×3 = 232 243 200 000
video+audio:
362 797 056 000 000 + 232 243 200 000 = 363 029 299 200 000
So if above is correct, It's good enough storage to hold almost enough for 3 hours of lossless non-compressed top of the line video and audio.
But can it transfer data at this rate?
10800×4320×120×48/8+192000×(22+2+4)×32/8=
33 613 824 000 Bytes per second
Update: There are audio options for even more channels available than listed here. (the 22+2+4, like 24+1+10, or 8+1+4+4). Audio is only small percentage the total data used even if the number of channels is maxed out from a merger of these. (24+2+10+4 ? 10/7 the audio amount above)
Question: How much data can the smaller ones hold?