I need some knowledge. real quick

[sepuko]

since nobody in the general software disucssion was able to answer me one simple question i'm gona ask here:
ho to turn this: /x./y.z+x./y./z+x./y.z=
into this: =/y.(x+z)
where "/" means "opposite". the equation is right i just need to see the steps.
10x in advance

 

[sepuko]

binary math. remember?
x+y or =)>-
x.y and =D-
/(x+y) nor =Do-
/(x.y) nand =)>o-
x(+)y xor =))>-
x=/x=0 const0
x=/x=1 const1
x=/x opposite result -|>o-
=x sameness -|>-

 

[crizazykid2]

Whew man, I dunno...way over my head. Keep the next post in english...aight?

 

[offgreen]

What is this, homework help?

 

[Vile]

Lol looks like it. Sorry I can't help.

 

[old_times]

Alright, dont expect me to do ur homework, but here is the hint:

* factorize /y from first and third expressions of left side of equation which is:
/x./y.z+x./y./z+x./y.z= /y(/x.z + x.z) + x./y./z

* Quite evidently (/x.z + x.z) = z (binary operations) now you have
/y(/x.z + x.z) + x./y./z = /y.z + x./y./z

* Factorize /y
/y.z + x./y./z = /y( z + x./z)
thats it => z or x not z is z or x - rewrite z



Right?!

 

[sepuko]

10X very much man! that was not my homework though. I'm trying to learn but the info i can get here(where i live) is poor...

 

[old_times]

(where i live) is poor...

You won’t say that to my Polish friend!