If I have a circuit that has a resistor of 4.7K Ohma then split into a parallel

[ross_18]

If I have a circuit that has a resistor of 4.7K Ohma then split into a parallel circuit having a resistor ( one being 82K and the other being 47K Ohms) on each line. The circuit then joins together again. There is a 120v power supply.
How do I calculate the resistance and current and what would be the total circuit’s current be?

 

[suat]

Total resistance i: 29876 ohms

Total current is: 3.47 mAmps

The resistance calculation is: 4700 + ( 1/( 1/82000 + 1/ 47000) ) = 29875.969 rounded to 29876 ohms

The current calculation is: 120 / 29876 = 3.470615 E -3 Amperes rounded to 3.47 mA.

If you want to know the currents on 82K resistor and 47K resistor, then you can solve the two equations

(1) 82000 * I1 = 47000 * I2

(2) I1 + I2 = 3.47 E-3

where I1 is the current flowing thru 82K and I2 is the one flowing thru 47K. * indicates multiplication ( multiplied by )

Note: the above simple calculations are based on the assumption that the voltage is 120 VDC, not 120 VAC.