Question Intel chipset diagram from 2004

[Koblerville]

Hello,

Please see my questions below about this data taken from a 2004-era Intel chipset diagram with memory controller hub 82925XE and P4 Extreme Edition CPU:
FSB/Mem: 2 DIMMs/channel * 2
1066/800 DDR2-533/400
4 GB
The diagram shows two memory banks each with one channel leading to the memory controller hub with a combined throughput of 8.5 GBs. The FSB also shows 8.5 GBs as its throughput.

1) Based on the red text above, is it accurate to say both memory banks are populated with one stick each of DDR2-533 RAM? 533 X 8 = PC2-4200 X 2 channels = 8.5 GBs throughput?
2) Where does the 1066 value above fit into this scenario?
3) If all four DIMM slots might be filled with a memory stick, what combination of DDR2 DIMMs would make that up? The manual says only DDR2 is supported.
AND I have one more question arising from the following info from the manual:
"The memory controller hub supports 32-bit host addressing decoding up to 4 GB of the processor's memory address space".
Seems like 4 GB is the maximum RAM this mobo can handle.
4) Can we express this addressability as an equation? If so, what?
Thank you.
James Hazuga

 

[kanewolf]

) Where does the 1066 value above fit into this scenario?

1066 is the DDR (double data rate) value. The memory can transfer data on the leading and trailing edge of the clock cycle. So the effective transfer rate is twice the clock speed (533).

 

[Eximo]

Two memory channels, two memory banks. Aside from the double data rate, theoretically as long as you have matching data being sent to both channels you can achieve double the bandwidth of the memory data rate. This is why DDR through DDR4 dual channel configurations are so important for PC performance. DDR5 cheats a little in having 2 memory banks per channel. (2x32)x2 rather than 2x64

PC4200 x2 is the answer you are seeking for a maximum bandwidth figure yes.

 

[Koblerville]

Two memory channels, two memory banks. Aside from the double data rate, theoretically as long as you have matching data being sent to both channels you can achieve double the bandwidth of the memory data rate. This is why DDR through DDR4 dual channel configurations are so important for PC performance. DDR5 cheats a little in having 2 memory banks per channel. (2x32)x2 rather than 2x64

PC4200 x2 is the answer you are seeking for a maximum bandwidth figure yes.

Two memory channels, two memory banks (total), and PC4200x2 add up right to the above stated throughput. Yet the description in red above (copied from the diagram) seems to state two DIMMs per channel resulting in four DIMM slots. Should "2 DIMMs/channel" really be stated as 1 DIMM per channel or am I misunderstanding "2 DIMMs/channel"?

 

[Eximo]

No, each memory channel, in this configuration, can have two memory sticks. Having four doesn't get you quad channel memory, just the two larger memory banks. Though there are quad channel boards with only 4 slots (typical would be 8 slots)

1x8GB + 2x4GB is often an acceptable dual channel configuration for example.

1x8GB + 1x4GB may offer the first 8GB in dual channel mode, with the remaining 4GB only available in single channel mode.

8400 MB/s maximum for the first 8GB, then 4GB at 4200 MB/s

More recent memory is measured in MT/s or 1 million MB/s