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Hey All,
I have been playing quite a few "star" vampire decks lately and wanted
to do some number crunching. I think these numbers are pretty darn
close (maybe have some rounding errors), but I welcome anyone to check
my work.
This mainly came from conventional wisdom saying that 4 vampires in 12
is how many you want if you want to see your chosen vampire, but 5 in
12 is what you should use if you *need* your chosen vampire. As such, I
have been often using 4/13 or 5/13 in certain decks because I think
there must be a better way. I finally got around to crunching the
numbers and thought I'd share.
Jeff
===========================
CRYPT DRAW PROBABILITIES
Here's the formula you need:
% = 100(n choose m)(12-n choose 4-m)/(12 choose 4)
where 'n' is the number of copies of the vampire in question and 'm'
is the number of copies of that vampire that you're looking for the
odds on. (Note that this presumes that you have a crypt of 12 and are
initially drawing 4. Otherwise you'll need to modify the 12 and the
4.) I'm using (x choose y) to represent:
(x choose y) = x!/((x-y)!y!)
which is the standard form for the number of distinct combinations of
y in x.
TWELVE (12) VAMPIRE CRYPT
# of copies \ % odds of drawing
0 1 2 3 4
0 100.0 0 0 0 0
1 66.7 33.3 0 0 0
2 42.4 48.5 9.1 0 0
3 25.5 50.9 21.8 1.8 0
4 14.1 45.3 33.9 6.5 0.2
5 7.1 35.4 42.4 14.1 1.0
6 3.0 24.2 45.5 24.2 3.0
THIRTEEN (13) VAMPIRE CRYPT
# of copies \ % odds of drawing
0 1 2 3 4
0 100.0 0 0 0 0
1 69.2 30.8 0 0 0
2 46.2 46.2 7.7 0 0
3 29.4 50.3 18.9 1.4 0
4 17.7 47.0 30.2 5.0 0.1
5 9.7 39.2 39.2 11.2 0.7
6 4.8 29.4 44.1 19.6 2.1
COMBINED TABLE FOR POPULAR COMBINATIONS (#/crypt size)
# of copies \ % odds of drawing
0 1 2 3 4 1 or 2
3/12 25.5 50.9 21.8 1.8 0 72.7
4/13 17.7 47.0 30.2 5.0 0.1 77.2
4/12 14.1 45.3 33.9 6.5 0.2 79.2
5/13 9.7 39.2 39.2 11.2 0.7 78.4
5/12 7.1 35.4 42.4 14.1 1.0 77.8
LIKELIHOOD OF SEEING CHOSEN VAMPIRE EACH OF SEVERAL GAMES
Distribution \ Non-Zero Chance in 1/3/4 Games
1G 3G 4G
3/12 74.5 41.3 30.8
4/13 82.3 55.7 45.9
4/12 85.9 63.4 54.4
5/13 91.3 73.6 66.5
5/12 92.9 80.2 74.5
COMMENTARY
With 3/12 distribution:
* You are more than 50% likely to see your chosen vampire in any game.
With 4/13 distribution:
* You are more likely to see 2 of your chosen vampire than zero in any
game.
* You are more than 50% likely to see your chosen vampire
in all rounds of a 2+F tournament.
With 4/12 distribution:
* You are nearly 2/3 likely to see your chosen vampire
in all rounds of a 2+F tournament.
* You are more than 50% likely to see your chosen vampire
in all rounds of a 3+F tournament.
With 5/13 distribution:
* You are more likely to see 3 of your chosen vampire than 0 in any
game.
* You are nearly 3/4 likely to see your chosen vampire
in all rounds of a 2+F tournament.
* You are nearly 2/3 likely to see your chosen vampire
in all rounds of a 3+F tournament.
With 5/12 distribution:
* You are over 4/5 likely to see your chosen vampire
in all rounds of a 2+F tournament.
* You are nearly 3/4 likely to see your chosen vampire
in all rounds of a 3+F tournament.
Hey All,
I have been playing quite a few "star" vampire decks lately and wanted
to do some number crunching. I think these numbers are pretty darn
close (maybe have some rounding errors), but I welcome anyone to check
my work.
This mainly came from conventional wisdom saying that 4 vampires in 12
is how many you want if you want to see your chosen vampire, but 5 in
12 is what you should use if you *need* your chosen vampire. As such, I
have been often using 4/13 or 5/13 in certain decks because I think
there must be a better way. I finally got around to crunching the
numbers and thought I'd share.
Jeff
===========================
CRYPT DRAW PROBABILITIES
Here's the formula you need:
% = 100(n choose m)(12-n choose 4-m)/(12 choose 4)
where 'n' is the number of copies of the vampire in question and 'm'
is the number of copies of that vampire that you're looking for the
odds on. (Note that this presumes that you have a crypt of 12 and are
initially drawing 4. Otherwise you'll need to modify the 12 and the
4.) I'm using (x choose y) to represent:
(x choose y) = x!/((x-y)!y!)
which is the standard form for the number of distinct combinations of
y in x.
TWELVE (12) VAMPIRE CRYPT
# of copies \ % odds of drawing
0 1 2 3 4
0 100.0 0 0 0 0
1 66.7 33.3 0 0 0
2 42.4 48.5 9.1 0 0
3 25.5 50.9 21.8 1.8 0
4 14.1 45.3 33.9 6.5 0.2
5 7.1 35.4 42.4 14.1 1.0
6 3.0 24.2 45.5 24.2 3.0
THIRTEEN (13) VAMPIRE CRYPT
# of copies \ % odds of drawing
0 1 2 3 4
0 100.0 0 0 0 0
1 69.2 30.8 0 0 0
2 46.2 46.2 7.7 0 0
3 29.4 50.3 18.9 1.4 0
4 17.7 47.0 30.2 5.0 0.1
5 9.7 39.2 39.2 11.2 0.7
6 4.8 29.4 44.1 19.6 2.1
COMBINED TABLE FOR POPULAR COMBINATIONS (#/crypt size)
# of copies \ % odds of drawing
0 1 2 3 4 1 or 2
3/12 25.5 50.9 21.8 1.8 0 72.7
4/13 17.7 47.0 30.2 5.0 0.1 77.2
4/12 14.1 45.3 33.9 6.5 0.2 79.2
5/13 9.7 39.2 39.2 11.2 0.7 78.4
5/12 7.1 35.4 42.4 14.1 1.0 77.8
LIKELIHOOD OF SEEING CHOSEN VAMPIRE EACH OF SEVERAL GAMES
Distribution \ Non-Zero Chance in 1/3/4 Games
1G 3G 4G
3/12 74.5 41.3 30.8
4/13 82.3 55.7 45.9
4/12 85.9 63.4 54.4
5/13 91.3 73.6 66.5
5/12 92.9 80.2 74.5
COMMENTARY
With 3/12 distribution:
* You are more than 50% likely to see your chosen vampire in any game.
With 4/13 distribution:
* You are more likely to see 2 of your chosen vampire than zero in any
game.
* You are more than 50% likely to see your chosen vampire
in all rounds of a 2+F tournament.
With 4/12 distribution:
* You are nearly 2/3 likely to see your chosen vampire
in all rounds of a 2+F tournament.
* You are more than 50% likely to see your chosen vampire
in all rounds of a 3+F tournament.
With 5/13 distribution:
* You are more likely to see 3 of your chosen vampire than 0 in any
game.
* You are nearly 3/4 likely to see your chosen vampire
in all rounds of a 2+F tournament.
* You are nearly 2/3 likely to see your chosen vampire
in all rounds of a 3+F tournament.
With 5/12 distribution:
* You are over 4/5 likely to see your chosen vampire
in all rounds of a 2+F tournament.
* You are nearly 3/4 likely to see your chosen vampire
in all rounds of a 3+F tournament.