I have a 2600K and I'm trying to overclock. First I turned SpeedStep off. My Vcore is set at auto so I only need to change the multiplier. When I changed my multiplier to 43 (for the clock to equal 4.3GHz), my Vcore automatically becomes 1.336v. I'm pretty sure everything so far is great.
My problem is that at whatever multiplier change (I went as low as 3.9GHz), (and my Vcore changes automatically and is sufficient), when I first turn on my computer, it turns off after 5 seconds and has to turn on again in order to boot.
People keep telling my that this problem is due to insufficient voltage, so I'm thinking, at what voltage (manually) should the Vcore be set with a multiplier of 43?
Please answer my question and help, I'm really getting stuck!
My problem is that at whatever multiplier change (I went as low as 3.9GHz), (and my Vcore changes automatically and is sufficient), when I first turn on my computer, it turns off after 5 seconds and has to turn on again in order to boot.
People keep telling my that this problem is due to insufficient voltage, so I'm thinking, at what voltage (manually) should the Vcore be set with a multiplier of 43?
Please answer my question and help, I'm really getting stuck!